1/v-4-4/v+2=-3/v^2-2v-8

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Solution for 1/v-4-4/v+2=-3/v^2-2v-8 equation: 



1/v-4-4/v+2=-3/v^2-2v-8

We move all terms to the left:

1/v-4-4/v+2-(-3/v^2-2v-8)=0



Domain of the equation: v!=0

v∈R





Domain of the equation: v^2-2v-8)!=0

v∈R



We add all the numbers together, and all the variables

1/v-4/v-(-3/v^2-2v-8)-2=0

We get rid of parentheses

1/v-4/v+3/v^2+2v+8-2=0

We calculate fractions

We do not support evpression: v^3

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